P=The power P in watts
V=the voltage V in volts
I=the current I in amps
So that you can define Power in watts are equal to V in volts times the Current(I) in amps
or you can re-write formula like this
Let’s take an example
Example#1
We need to find out the power(P) in watts where the current(I) flow is 5A and the voltage(V) is 10V In the circuit.
Apply formula for the solutions
P = 10V × 5A = 50W
P=The power P in watts
PF=the power factor PF
I=the phase current I in amps
V= the Root Mean Square voltage V in volts
So that you can define power(P in watts) are equal to the PF times the current(I) flow in amps times volts(V)
or you can re-write this formula like that
Let’s take an example
Example#2
We need to find out the power(P) in watts where the PF is 0.8 and the current Flow is 5A and Root Mean Square voltage is 100V in the circuit
Apply formula for the solution
P = 0.8 × 5A × 100V = 400W
P= power P in watts
PF=the power factor PF
I=the phase current I in amps
V=the line to line Root Mean Square voltage VL-L in volts
So that you can define Power(P) in watts are equal to 1.732 times PF times current(I) flow in amps times volts(V)
or you can re-write formula like that
Let’s take an example
Example#3
Find out the power(P) in watts where the PF is 0.8 and the current Flow is 5A and the Root Mean Square voltage is 100V in the circuit.
Apply formula for the solutions
P(W) = 1.732 × 0.8 × 5A × 100V = 692.8W
Calculation with line to neutral voltage
P(W)=The power P in watts (W)
PF=Power factor
I(A)=phase current I in amps (A)
VL-L(V)= the line to neutral RMS voltage VL-N in volts (V)
Let’s take an example
Example#4
Find out the power(P) in watts where the PF is 0.8 and the current Flow is 5A and the Root Mean Square voltage is 50V in the circuit.
Apply formula for the solutions
P(W) = 3 × 0.8 × 5A × 50V = 600W
So If we want to calculate the Watts from volts then we need the value of current(I) without knowing the current in the circuit we can not calculate the watts.
For Example,if we take a current of 4 amps in the circuit then we can easily perform the following conversion